Covalent Lewis Dot Structure Calculator

The sharing of pair of electrons between two atoms is referred to as a covalent bond. Normally, each atom that is participating in the covalent bond formation, contributes equal number of electrons to form pair(s) of electrons. The pair of electrons shared between the atoms is also known as bond pair.

The bond pair is strongly attracted by the nuclei of two atoms and thus by reducing the potential energy of them. This is the driving force of formation of covalent bond, which stabilizes the two atoms.

. (3c) Lewis dot diagrams are used to represent valence electrons in an element. Structural formulas show the arrangements of atoms and bonds in a molecule and are represented by Lewis dot structures. Draw Lewis dot diagrams to represent valence electrons in elements and draw Lewis dot structures to show covalent bonding. Nov 24, 2018 Use information from step 4 and 5 to draw the CH 4 lewis structure. Easy Way – Treat them like Puzzle Pieces Lewis structure of CH 4. Alternatively a dot method can be used to draw the CH 4 Lewis structure. Calculate the total valence electrons in the molecule. Total=8; This unit is part of the Chemistry library.

The distance between the nuclei of two atoms when their potential energy reaches a minima is also known as bond length. The forces of attraction between these two atoms are maximum at this point. However, the repulsion forces dominate over the attraction forces when these atoms are bring further closer together and thus by increasing the potential energy.

If two atoms share only one bond pair, that bond is referred to as a single bond. If two bond pairs are shared, that is known as a double bond. Likewise, a triple bond is formed when the atoms share three bond pairs.

A covalent bond is formed between two atoms when their electronegativity difference is less than 1.7 on Pauling's scale. Usually it is formed between two nonmetals.

Polarity of covalent bond: The bond pair is equally shared in between two atoms when the electronegativity difference between them is zero or nearer to zero. In this case, neither of the atoms gets excess of electron density and hence carry no charge. This is called non polar covalent bond.

However, when there is a considerable difference in the electronegativity, the bond pair is no longer shared equally between the atoms. It is shifted slightly towards the atom with higher electronegativity by creating partial negative charge (represented by δ-) over it. Whereas, the atom with less electronegativity gets partial positive charge (represented by δ+). This type of bond is also referred to as polar covalent bond.

Coordinate covalent bond: Some times, during the formation of covalent bond, the shared pair is entirely contributed by only one atom This is called as coordinate covalent bond or dative bond.

LEWIS DOT MODEL

To explain the formation of covalent bond, a simple qualitative model was developed by Gilbert Newton Lewis in 1916.

According to this model:

* Octet rule: The inert gas atoms with 8 electrons in their outer shell (also known as valence shell) are highly stable. The Helium atom with 2 electrons in its outer shell is also stable.

Hence every atom tries to get nearest inert gas configuration by sharing electrons. The bond formed due to sharing of electrons is otherwise known as a covalent bond.

* Only the electrons in the valence shell are contributed for sharing. The inner electrons, which are also known as core electrons do not participate in the bond formation.

* In the formation of covalent bond between two atoms, each atom contributes its valence electrons to form pair(s) of electrons, which in turn is/are shared by both of them.

Due to sharing of electrons, each atom gets nearest inert gas configuration.

Covalency : The number of electrons contributed by the atom of an element in the formation of covalent compound is known as covalency of that element.

In Lewis dot model, the electrons in the valence shell of the atom are shown as dots around it.

ILLUSTRATIONS OF LEWIS DOT STRUCTURES

1) H2 molecule:

* The electronic configuration of hydrogen is 1s1. It requires one electron to get the configuration of Helium.

* Therefore, during the formation of H2 molecule, each hydrogen atom contributes one electron to form a pair of electrons. This in turn is shared between the two hydrogen atoms to form a covalent bond.

* Thus in H2 molecule, each hydrogen atom gets its nearest inert gas: Helium's configuration, 1s2.

* The covalency of hydrogen is 1.

* The Lewis dot structure for H2 molecule is shown below. Note that each hydrogen gets two electrons after forming the bond. The bond between two hydrogen atoms can be shown as a line, which represents a bond pair of electrons.

Note: The bond between two hydrogen atoms is non polar since the electronegativity difference is zero.

2) Cl2 molecule:

* The electronic configuration of Cl is [Ne]3s23p5. There are 7 electrons in the outer shell.

* Therefore, in order to get the nearest inert gas: Argon's configuration, [Ne]3s23p6, each chlorine atom contributes one electron for the bond formation and form a bond pair, which is shared between the two chlorine atoms.

* Thus Cl2 molecule is formed with a covalent bond between two chlorine atoms.

* In Cl2 molecule, each Cl atom gets 8 electrons in its outer shell. See the diagram below.

The bond pair is also shown as a line. The electron pairs which do not participate in the bonding are known as lone pairs. There are three such lone pairs on each of the chlorine atom.

* Hence the covalency of chlorine is 1.

* Remember that, in the Lewis dot structures, only the electrons in the valence shell are shown.

Note: The bond between two chlorine atoms is non polar since the electronegativity difference is zero.

3) Hydrogen chloride (HCl):

* The electronic configuration of hydrogen is 1s1. It requires one electron to get the configuration of He.

* The electronic configuration of chlorine is [Ne]3s23p5. It also requires one electron to get the octet configuration.

* Hence, in the formation of HCl molecule, the hydrogen and chlorine atoms contribute one electron each for the bond formation.

Note: The bond between hydrogen and chlorine atoms is considerably polar, since the electronegativity difference between them is 3.5 - 2.1 = 1.4. However they do not form ionic bond since the e.n. difference is less than 1.7.

The hydrogen atom gets partial positive charge, whereas the chlorine atom gets partial negative charge. However, they are not completely ionized.

4) Methane (CH4):

* The electronic configuration of carbon is [He]2s22p2.

* The electronic configuration of hydrogen is 1s1. Hence it contributes this electron to get the nearest inert gas, Helium's configuration.

* The carbon atom forms four covalent bonds by contributing four of its valence electrons. It forms 4 bonds with four hydrogen atoms. Thus it gets octet configuration.

* Covalency of carbon is 4.

* There are no lone pairs on carbon in methane.

Note: The electronegativity difference between carbon (e.n. = 2.5) and hydrogen (e.n. = 2.1) is not considerable. Hence the covalent bond formed is practically considered as non polar.

5) Ammonia (NH3) :

* The electronic configuration of nitrogen is [He]2s22p3. Nitrogen require three electrons to complete the octet.

* The electronic configuration of hydrogen is 1s1 and hence in need of one electron to complete the shell.

* In the formation of Ammonia molecule, the nitrogen atom contributes 3 of its valence electrons to form three bond pairs which are shared with hydrogen atoms. Thus nitrogen forms 3 single bonds with three hydrogen atoms and gets the configuration of Neon.

* There is also one lone pair on nitrogen atom.

Calculator

* Covalency of nitrogen is 3.

Note: There is considerable polarity in N-H bond since the electronegativity difference between nitrogen (e.n. = 3.0) and hydrogen (e.n. = 2.1) is 0.9.

Being highly electronegative than hydrogen, the nitrogen atom gets partial negative charge, whereas the hydrogen atom gets partial positive charge.

6) H2O molecule :

* The electronic configuration of oxygen is [He]2s22p4. Hence it requires two more electrons to complete its octet.

* In the formation of water molecule, the oxygen atom contributes two of its valence electrons to form two bond pairs that are shared with two hydrogen atoms separately. Thus two bonds are formed by oxygen atom to get the configuration of Neon.

Lewis dot diagram calc

* There are also two lone pairs on oxygen atom.

* Covalency of oxygen is 2.

Note: The O-H bond is also considerably polar since the electronegativity difference between oxygen (e.n. = 3.5) and hydrogen (e.n. = 2.1) is 1.4.

Since the oxygen atom is more electronegative, it gets partial negative charge.

7) Dioxygen molecule (O2):

* In the formation of dioxygen molecule, each oxygen atom contributes 2 electrons to form 2 bond pairs, which are shared by the two oxygen atoms. Thus each oxygen atom gets Neon's configuration.

* There is a double bond between two oxygen atoms.

* However there are two lone pairs on each oxygen atom.

8) Dinitrogen molecule (N2):

* In the formation of Dinitrogen molecule, each nitrogen atom contributes 3 electrons to form 3 bond pairs, which in turn are shared by two nitrogen atoms. Each nitrogen atom gets Neon's configuration.

* Thus a triple bond between nitrogen atoms is formed.

* Each nitrogen also contains one lone pair.

9) Carbon dioxide molecule (CO2):

* The carbon atom contributes four of its valence electrons, whereas each oxygen atom contributes two electrons for the bond formation to complete their octets.

* There are two electron pairs shared between carbon and one of the oxygen atom i.e., a double bond, C=O is formed. There are two such C=O bonds in CO2 molecule.

Note: The C=O bond is polar due to electronegativity difference between carbon (e.n. = 2.1) and oxygen (e.n. = 3.5) is 1.4.

Question to ponder: What is the overall polarity of the carbon dioxide molecule? Is it polar or non polar?

Molecules violating octet rule:

1) BeCl2 (Beryllium chloride):

* The electronic configuration of Beryllium is 1s22s2.

* The electronic configuration of Chlorine is [Ne]3s23p5.

* During the formation of Beryllium chloride, the beryllium atom contributes its two valence electrons and forms two bond pairs. These are shared with chlorine atoms.

* In BeCl2 there are only four electrons in the valence shell of Be. However the Beryllium chloride is a relatively stable molecule. This is the violation of octet rule.

* Covalency of beryllium is 2.

Note: The beryllium atom may lose two of its valence electrons to get the nearest inert gas: Helium's configuration and form Be2+ ion. However, the electronegativity difference between Beryllium (e.n. = 1.5) and that of chlorine (e.n. = 3.0) is less than 1.7. Hence the bond between them has considerable covalent character rather than the ionic nature.

2) BCl3 (Boron trichloride):

* The electronic configuration of Boron is 1s22s22p1.

* During the formation of BCl3 molecule, the boron atom contributes 3 of its valence electrons to form three bond pairs with chlorine atoms.

* Thus there are only six electrons in the valence shell of boron atom in BCl3. However, still this molecule is stable. It is an electron deficient compound. It is also the violation of the octet rule.

* Covalency of boron is 3.

Note: The bond between boron (e.n. = 2.0) and chlorine (e.n. = 3.0) is covalent since the electronegativity difference between them is less than 1.7.

3) PCl5 (Phosphorous pentachloride):

* Electronic configuration of phosphorus is [Ne]3s23p3.

* Electronic configuration of chlorine is [Ne]3s23p5.

* In the formation of PCl5 molecule, phosphorus contributes five electrons in it's valence shell and forms five bonds with chlorine atoms.

* Thus there are 10 electrons in the valence shell of phosphorus in this molecule. It is a stable molecule, however, violating the octet rule.

* Covalency of phosphorus in this molecule is 5.

Covalent lewis dot structure calculator formula

4) SF6 (Sulphur hexafluoride) :

* The electronic configuration of Sulphur is [Ne]3s23p4.

Lewis

* The electronic configuration of Fluorine is [He]2s22p5.

* The fluorine atom requires one electron to complete its octet. Hence it contributes one electron for bonding.

* The Sulphur atom contributes six of its valence electrons to form 6 bonds with six fluorine atoms. Thus there are 12 electrons in the valence shell in sulphur atom.

* The SF6 molecule is quite stable even though it violates the octet rule.

* Covalency of sulphur in this molecule is 6.

DRAWBACKS OF LEWIS THEORY

* Lewis theory could not explain the geometry of molecules and bond angle in them.

* It could not explain why some molecules are violating the octet rule.

* This is a qualitative explanation for covalent bond only.

To fulfill these gaps and to explain the covalent bond formation quantitatively, the Valence bond theory (VBT) was put forwarded. You can find more insight into this theory in next section.

However it is important to learn VSEPR theory, another qualitative model, which was put forwarded to explain the shapes of molecules, before moving on to Valence bond theory.

< Ionic bondChemical bonding: TOCVSEPR Theory >
By Aditya vardhan Vutturi

ALL questions listed must be answered to earn credit for completing the text homework. Yes, even the Additional Exercises if they are present for this chapter.

Lewis

Covalent Compounds

(1) How do atoms form covalent bonds? What is the easiest way to distinguish a covalent bond from an ionic bond?

(2) For each of the following elements, draw their Lewis dot structures.

  1. Sulfur
  2. Boron
  3. Iodine
  4. Silicon
  5. ​Phosphorus

(3) Study the given Lewis structure and provide the following information:

  1. Draw in any lone pairs that are needed.
  2. How many bonding electrons does the carbon have? How many does Oxygen have?
  3. Is the octet of each atom in the molecule satisfied?
  4. How many single bonds are used in this molecule? How many double bonds?
  5. How many bonds are shared between the Carbon and Oxygen atoms? How many are shared between the Carbon and each Hydrogen?

(4) Answer each question regarding the following structure:

  1. Fill in all missing lone pairs
  2. How many bonding electrons does the Nitrogen have? How many non-bonding electrons does it have?
  3. How many bonding electrons do each Chlorine have? How many non-bonding electrons do they each have?
  4. How many electrons, in total, does Nitrogen share with all three Chlorines? Does each atom have an octet?
  5. ​Are the bonds formed in this molecule ionic or covalent?

(5) Draw the Lewis dot structures for each of the 7 diatomic elements in their diatomic states. Are these diatomic elements, when one atom is covalently bonded to another of the same element, considered molecules or compounds? Explain using the definition of whichever answer you choose.

(6) For each family or group number, describe the covalent bonding pattern found in organic compounds.

  1. Halogens
  2. Group 4A
  3. Group 6A
  4. Group 5A
  5. Noble Gases

(7) Sketch the Lewis configurations for the following molecules. Include all lone pairs in the sketch and determine how many total electrons are in each molecule.

  1. CH2Cl2
  2. HCN
  3. CH2O
  4. CH3CH2CH3
  5. ​CH3COOH (Hint: Both oxygens bond to the second carbon)

(8) What is an expanded octet? Which elements cannot form an expanded octet? Where on the periodic table are the elements that can form expanded octets located?

(9) Give the names of the following covalent compounds.

  1. N2O4
  2. SCl6
  3. CBr4
  4. P2O5
  5. ClF7

Three-Dimensional Shapes of Molecules

(10) Include the Lewis dot structure for each given molecule. Give both the electron geometry and molecular shape of the central atom(s).

  1. CH3F
  2. H2O
  3. NH2I
  4. CH2S

(11) If a central atom has three bonding groups surrounding it, how can you differentiate between the possible molecular shapes it can take on? What electron geometry, molecular shape and bond angles would such a molecule have?

(12) For each of the following molecules, tell whether they are two-dimensional or three-dimensional based on their electron geometry.

  1. NH3
  2. H2S
  3. CH2Cl2
  4. CH2S
  5. CO2

(13) What are the approximate bond angles in the given molecules?

  1. PBr3
  2. HNO
  3. CH3F
  4. CH2O
  5. CS2

(14) In each of the following molecules, give the central atom’s molecular shape and the approximate bond angles.

a. O=C=O

b.

c. NH3

d.

e.

(15) Use your knowledge of what you’ve learned so far to provide the Lewis dot structures, electron geometry, molecular shape, bond angles, number of lone pair electrons, and the number of shared pair electrons for each molecule given.

  1. CI2Br2
  2. NOF
  3. ClCN
  4. CH2O

(16) For each of the three carbons in this molecule, provide the requested information.

  1. The molecular shape of each carbon
  2. Is this molecule more likely to be two-dimensional or three dimensional?
  3. What is the bond angle of the CH2?
  4. What is the H-C-C bond angle?
  5. What is the C-C-N bond angle?

Modeling Exercises

(17) Construction of acetic acid, CH3COOH

  1. Obtain two carbons, four hydrogens, and two oxygens with six single-bond sticks and two double-bond sticks
  2. Sketch the Lewis dot structure to get an idea of how to put it together
  3. Construct the model to get a three-dimensional visual of acetic acid
  4. For each carbon atom, how many different electron groups, both bonding and non-bonding, surround them?
  5. Of those groups and for each carbon, respectively, how many are bonding and how many are non-bonding?
  6. What is the electron geometry around each carbon? Molecular shape?
  7. Is the majority of the molecule two-dimensional, or three-dimensional? Justify. (Hint: Try rotating some of the central atoms and looking at it from different angles.)
  8. What are the bond angles on each central atom (remember to include the oxygen in the -OH as one of the central atoms.)
  9. Why does one of the two oxygen atoms get treated as a central atom and not the other?

(18) Construction of acetonitrile, CH3CN

  1. Obtain two carbons, three hydrogens and a nitrogen, four single-bond sticks and three double-bond sticks.
  2. Sketch the Lewis dot structure of the molecule to determine its structure.
  3. Construct the model of the molecule for a visual representation.
  4. How many non-bonding electrons does each carbon have? Bonding electrons?
  5. Determine the electron geometry and molecular shape of each carbon.
  6. Is the nitrogen a central atom or not? Explain.
  7. What is the electron geometry of the nitrogen? What is the molecular shape?

Molecular Polarity

(19) Between the following pairs, which has the higher electronegativity?

  1. Oxygen and Nitrogen
  2. Sulfur and Oxygen
  3. Chlorine and Bromine
  4. Carbon and Silicon
  5. Phosphorus and Nitrogen

(20) Describe the trend in electronegativity as you move left and right across the periodic table. Does electronegativity increase to the right or the left? Now do the same for moving up and down; does electronegativity increase as you go up or down?

(21) Sketch each of the following molecules to help you determine whether they are polar or non-polar. Draw dipole arrows to indicate polarity in polar molecules.

  1. CCl4
  2. PH3
  3. HOCl
  4. CS2
  5. HCOOH

(22) Electronegativity is not the sole decider of polarity within a molecule. Keeping this in mind, determine if the following molecules are polar or not. If not, explain why.

  1. CH2F2
  2. CO2
  3. CH3CH3
  4. H2O
  5. CH3OCH3

Intermolecular Forces of Attraction

Covalent Lewis Dot Structure

(23) Are intermolecular forces considered to be bonds? Explain. Is an H-bond an exception?

(24) Which of the three intermolecular forces is the most common? List two other names that can be used to describe this interaction. What is its relative strength compared to the others?

(25) Explain why a dipole-dipole attraction is a stronger force than London Dispersion forces. What is the critical difference that makes this so?

(26) What is the dominant intermolecular forces in each of the following molecules?

Covalent Lewis Dot Structure Practice

  1. CH2CH2
  2. CH3OH
  3. HCN
  4. CH3OCH3
  5. NH3

(27) Water (H2O) is one of the most perfect H-bonding molecules we know of. Use your knowledge of H-bonding to explain why solid H2O (ice) floats in liquid H2O while in most other substances, the density of the solids is greater than their respective liquids.

Covalent Lewis Dot Structure Calculator Worksheet

(28) Intermolecular forces are significant for allowing molecules to do things that bonding alone will not allow for. Explain how something like DNA utilizes intermolecular forces to take on its helical shape without relying solely on covalent bonding.